LAB 2. WORKED EXAMPLES
Note: all numbers used are made up, but the techniques are correct.
1.
Find
the length in meters of a minute of longitude on the map.
103o 17 30 W 103o 15 W
23
cm
It
is 2750 m. if 2.5 = 2750 m, 1 = 2750/2.5 = 1100 m.
2. At 600 N, one
degree of longitude equals 55.8 km; one degree of latitude equals 111 km. Using
these equivalents, calculate the distance in km between the following
locations:
600 00' 00" N to 600
00' 00" N
1330 22' 45" W 1360 30'
50" W
LONGITUDE
is changing. The amount of change is 30 8' 5". 10 =
55.8 km, therefore 30 8' 5" =
3 x 55.8
+ 8
x 55.8/60
+ 5
x 55.8/3600
=
167.4 + 7.44 + 0.0775 = 174.9175 km = 174.918
km (round to 3 decimal places).
3.
What
would be the distance in miles of the following distance where one longitude
degree equals 45.2 miles:
40 20' 35" ?
Answer = 4 x 45.2
+ 20 x
45.2/60
+ 35 x
45.2/3600
=
180.8 + 15.06666666667 + 0.4394444444444 = 196.3061111111 miles = 196.306 miles.
4.
Give precise latitude and longitude coordinates of the following location:
3.5
cm 7.2
cm
From
Q. 1 above, we know that 1 longitude = 9.2 cm (23/2.5). Therefore the
longitude will be 103o 15 +
7.2/9.2
x 1 or 103o 15 + 7.2/9.2 x 60
=
103o 15 + 47 = 103o
15 47 W (Round to nearest second).
Lets
assume we have already calculated that 1 of latitude = 11.5 cm on this map.
Therefore, the latitude of the point is:
29o
15 + 3.5/11.5 x 1 or 29o 15 + 3.5/11.5 x 60
=
29o 15 + 18 = 29o
15 18 N (Round to nearest second).
5.
Give the 6-digit UTM grid reference for the following location:
3238000 3237000 668000 3/10 of a grid square 8/10 of a grid square
669000
The
actual UTM reference for the point is 668800 m east, 3237300 m north. By
convention, for a 6-digit UTM reference this is written as 688373 (note
that the easting is always given first).
6.
What is found at the following UTM grid reference: 697379
697 379
The
answer is a cave.
7.
How many kilometers a) east and b) north are between UTM references 123456 and
333777?
We
know that two zeros have been left off of these UTM references; we must return
the two zeros to calculate the distances:
a) easting separation = 33300 -12300 m =
21000 m = 21 km.
b) northing separation = 77700 45600 m =
32100 m = 32.1 km.